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文章目錄
- SQL基本操作
- 1 設(shè)計(jì)表操作
- 1.1 關(guān)系表字段
- 1.2 關(guān)系表創(chuàng)建
- 1.3 關(guān)系表數(shù)據(jù)
- 1.4 關(guān)系表關(guān)系
- 2 SQL操作
- 2.1 SQL 1-10
- 2.2 SQL 11-20
- 2.3 SQL 21-30
- 2.4 SQL 31-40
- 2.5 SQL 41-50
SQL基本操作
1 設(shè)計(jì)表操作
1.1 關(guān)系表字段
- 1 學(xué)生表 student
s_id | s_name | s_birth | s_sex |
---|---|---|---|
學(xué)生編號 | 學(xué)生姓名 | 學(xué)生年月 | 學(xué)生性別 |
- 2 課程表 course
c_id | c_name | t_id |
---|---|---|
課程編號 | 課程名稱 | 教師標(biāo)號 |
- 3 教師表 teacher
t_id | t_name |
---|---|
教師編號 | 教師姓名 |
- 4 成績表 score
s_id | c_id | s_score |
---|---|---|
學(xué)生編號 | 課程編號 | 課程分?jǐn)?shù) |
1.2 關(guān)系表創(chuàng)建
- 1 創(chuàng)建 student 表
CREATE TABLE student(
s_id VARCHAR(20),
s_name VARCHAR(20) NOT NULL DEFAULT '',
s_birth VARCHAR(20) NOT NULL DEFAULT '',
s_sex VARCHAR(10) NOT NULL DEFAULT '',
PRIMARY KEY(s_id)
) ENGINE=INNODB DEFAULT CHARSET=utf8;
- 2 創(chuàng)建 course 表
CREATE TABLE course(
c_id VARCHAR(20),
c_name VARCHAR(20) NOT NULL DEFAULT '',
t_id VARCHAR(20) NOT NULL,
PRIMARY KEY(c_id)
) ENGINE=INNODB DEFAULT CHARSET=utf8;
- 3 創(chuàng)建 teacher 表
CREATE TABLE teacher(
t_id VARCHAR(20),
t_name VARCHAR(20) NOT NULL DEFAULT '',
PRIMARY KEY(t_id)
) ENGINE=INNODB DEFAULT CHARSET=utf8;
- 4 創(chuàng)建score表
CREATE TABLE score(
s_id VARCHAR(20),
c_id VARCHAR(20),
s_score INT(3),
PRIMARY KEY(s_id,c_id)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
1.3 關(guān)系表數(shù)據(jù)
INSERT INTO student VALUES('01' , '趙雷' , '1990-01-01' , '男');
INSERT INTO student VALUES('02' , '錢電' , '1990-12-21' , '男');
INSERT INTO student VALUES('03' , '孫風(fēng)' , '1990-05-20' , '男');
INSERT INTO student VALUES('04' , '李云' , '1990-08-06' , '男');
INSERT INTO student VALUES('05' , '周梅' , '1991-12-01' , '女');
INSERT INTO student VALUES('06' , '吳蘭' , '1992-03-01' , '女');
INSERT INTO student VALUES('07' , '鄭竹' , '1989-07-01' , '女');
INSERT INTO student VALUES('08' , '王菊' , '1990-01-20' , '女');
INSERT INTO course VALUES('01' , '語文' , '02');
INSERT INTO course VALUES('02' , '數(shù)學(xué)' , '01');
INSERT INTO course VALUES('03' , '英語' , '03');
INSERT INTO teacher VALUES('01' , '張雪峰');
INSERT INTO teacher VALUES('02' , '李佳琦');
INSERT INTO teacher VALUES('03' , '王思聰');
INSERT INTO score VALUES('01' , '01' , 80);
INSERT INTO score VALUES('01' , '02' , 90);
INSERT INTO score VALUES('01' , '03' , 99);
INSERT INTO score VALUES('02' , '01' , 70);
INSERT INTO score VALUES('02' , '02' , 60);
INSERT INTO score VALUES('02' , '03' , 80);
INSERT INTO score VALUES('03' , '01' , 80);
INSERT INTO score VALUES('03' , '02' , 80);
INSERT INTO score VALUES('03' , '03' , 80);
INSERT INTO score VALUES('04' , '01' , 50);
INSERT INTO score VALUES('04' , '02' , 30);
INSERT INTO score VALUES('04' , '03' , 20);
INSERT INTO score VALUES('05' , '01' , 76);
INSERT INTO score VALUES('05' , '02' , 87);
INSERT INTO score VALUES('06' , '01' , 31);
INSERT INTO score VALUES('06' , '03' , 34);
INSERT INTO score VALUES('07' , '02' , 89);
INSERT INTO score VALUES('07' , '03' , 98);
1.4 關(guān)系表關(guān)系
2 SQL操作
2.1 SQL 1-10
1、查詢 “01” 課程比 “02” 課程成績高的學(xué)生的信息及課程分?jǐn)?shù)
SELECT a.* ,b.s_score AS 01_score,c.s_score AS 02_score
FROM student a
JOIN score b
ON a.s_id=b.s_id AND b.c_id='01'
LEFT JOIN Score c
ON a.s_id=c.s_id AND c.c_id='02' OR c.c_id = NULL
WHERE b.s_score>c.s_score;
2、查詢"01"課程比"02"課程成績低的學(xué)生的信息及課程分?jǐn)?shù)
SELECT a.* ,b.s_score AS 01_score,c.s_score AS 02_score
FROM student a
LEFT JOIN score b
ON a.s_id=b.s_id AND b.c_id='01' OR b.c_id=NULL
JOIN score c
ON a.s_id=c.s_id AND c.c_id='02'
WHERE b.s_score<c.s_score;
3、查詢平均成績大于等于60分的同學(xué)的學(xué)生編號和學(xué)生姓名和平均成績
SELECT b.s_id,b.s_name,ROUND(AVG(a.s_score),2) AS avg_score
FROM student b
JOIN score a ON b.s_id = a.s_id
GROUP BY b.s_id,b.s_name
HAVING ROUND(AVG(a.s_score),2)>=60;
4、查詢平均成績小于60分的同學(xué)的學(xué)生編號和學(xué)生姓名和平均成績
(包括有成績的和無成績的)
SELECT b.s_id,b.s_name,ROUND(AVG(a.s_score),2) AS avg_score
FROM student b
LEFT JOIN score a
ON b.s_id = a.s_id
GROUP BY b.s_id,b.s_name
HAVING ROUND(AVG(a.s_score),2)<60
UNION
SELECT a.s_id,a.s_name,0 AS avg_score
FROM student a
WHERE a.s_id NOT IN (SELECT DISTINCT s_id FROM score);
5、查詢所有同學(xué)的學(xué)生編號、學(xué)生姓名、選課總數(shù)、所有課程的總成績
SELECT a.s_id,a.s_name,
COUNT(b.c_id) AS sum_course,
SUM(b.s_score) AS sum_score
FROM student a
LEFT JOIN score b
ON a.s_id=b.s_id
GROUP BY a.s_id,a.s_name;
6、查詢"李"姓老師的數(shù)量
SELECT COUNT(t_id) FROM teacher WHERE t_name LIKE '李%';
7、查詢學(xué)過"張雪峰"老師授課的同學(xué)的信息
SELECT a.*
FROM student a
JOIN score b
ON a.s_id=b.s_id
WHERE b.c_id IN(
SELECT c_id FROM course WHERE t_id =(
SELECT t_id FROM teacher WHERE t_name = '張雪峰'));
8、查詢沒學(xué)過"張雪峰"老師授課的同學(xué)的信息
SELECT c.*
FROM student c
WHERE c.s_id NOT IN(
SELECT a.s_id FROM student a JOIN score b ON a.s_id=b.s_id
WHERE b.c_id IN(
SELECT c_id FROM course WHERE t_id =(
SELECT t_id FROM teacher WHERE t_name = '張雪峰')));
9、查詢學(xué)過編號為"01"并且也學(xué)過編號為"02"的課程的同學(xué)的信息
SELECT a.*
FROM student a,score b,score c
WHERE a.s_id = b.s_id
AND a.s_id = c.s_id
AND b.c_id='01'
AND c.c_id='02';
10、查詢學(xué)過編號為"01"但是沒有學(xué)過編號為"02"的課程的同學(xué)的信息
SELECT a.*
FROM student a
WHERE a.s_id IN
(SELECT s_id FROM score WHERE c_id='01' )
AND a.s_id NOT IN
(SELECT s_id FROM score WHERE c_id='02')
2.2 SQL 11-20
11、查詢沒有學(xué)全所有課程的同學(xué)的信息
SELECT s.*
FROM student s
WHERE s.s_id IN(
SELECT s_id FROM score WHERE s_id NOT IN(
SELECT a.s_id FROM score a
JOIN score b ON a.s_id = b.s_id AND b.c_id='02'
JOIN score c ON a.s_id = c.s_id AND c.c_id='03'
WHERE a.c_id='01'))
12、查詢至少有一門課與學(xué)號為"01"的同學(xué)所學(xué)相同的同學(xué)的信息
SELECT *
FROM student
WHERE s_id IN(
SELECT DISTINCT a.s_id FROM score a WHERE a.c_id IN(
SELECT a.c_id FROM score a WHERE a.s_id='01'));
13、查詢和"01"號的同學(xué)學(xué)習(xí)的課程完全相同的其他同學(xué)的信息
方式1:
SELECT * FROM student WHERE s_id IN(
SELECT DISTINCT d.s_id FROM (
SELECT b.s_id , c.c_id FROM (
SELECT s.s_id,COUNT(a.c_id) c_num
FROM student s,score a
WHERE s.s_id = a.s_id
GROUP BY s.s_id
HAVING c_num=(SELECT COUNT(c_id) FROM score WHERE s_id='01')) b
JOIN score c
WHERE b.s_id = c.s_id AND c.c_id IN (
SELECT c_id FROM score WHERE s_id='01')) d)
AND s_id !='01';
第一步:先查詢s_id是01的學(xué)生的課程號和課程號的個(gè)數(shù)
SELECT COUNT(c_id) FROM score WHERE s_id='01'
SELECT c_id FROM score WHERE s_id='01'
第二步:求學(xué)生c_id的個(gè)數(shù)是3的s_id,并且c_id在第一步查詢的c_id的值內(nèi)
SELECT b.s_id , c.c_id FROM (
SELECT s.s_id,COUNT(a.c_id) c_num
FROM student s,score a
WHERE s.s_id = a.s_id
GROUP BY s.s_id
HAVING c_num=(
SELECT COUNT(c_id)
FROM score WHERE s_id='01')) b
JOIN score c WHERE b.s_id = c.s_id AND c.c_id IN (
SELECT c_id FROM score WHERE s_id='01')
第三步:查詢第二步的結(jié)果中的s_id
第四步:查詢學(xué)生信息且s_id在第三步的s_id中 并且去除掉編號是01的學(xué)生信息
方式2:
SELECT *
FROM student
WHERE s_id IN (
SELECT s_id FROM (
SELECT s_id, COUNT( s_id ) cou
FROM (
SELECT * FROM score WHERE s_id IN (
SELECT s_id FROM (
SELECT s_id, COUNT( s_id ) COUNT
FROM score WHERE s_id != '01' GROUP BY s_id ) t1
WHERE t1.count = (
SELECT COUNT( c_id ) FROM score WHERE s_id = '01' ))) t3
WHERE t3.c_id IN (
SELECT c_id FROM score WHERE s_id = '01' ) GROUP BY s_id ) t4
WHERE t4.cou=(SELECT COUNT( c_id ) FROM score WHERE s_id = '01'))
– 14、查詢沒學(xué)過"張三"老師講授的任一門課程的學(xué)生姓名
select a.s_name from student a where a.s_id not in (
select s_id from score where c_id =
(select c_id from course where t_id =(
select t_id from teacher where t_name = ‘張三’))
group by s_id);
– 15、查詢兩門及其以上不及格課程的同學(xué)的學(xué)號,姓名及其平均成績
select a.s_id,a.s_name,ROUND(AVG(b.s_score)) from
student a
left join score b on a.s_id = b.s_id
where a.s_id in(
select s_id from score where s_score<60 GROUP BY s_id having count(1)>=2)
GROUP BY a.s_id,a.s_name
– 16、檢索"01"課程分?jǐn)?shù)小于60,按分?jǐn)?shù)降序排列的學(xué)生信息
select a.*,b.c_id,b.s_score from
student a,score b
where a.s_id = b.s_id and b.c_id=‘01’ and b.s_score<60 ORDER BY b.s_score DESC;
– 17、按平均成績從高到低顯示所有學(xué)生的所有課程的成績以及平均成績
select a.s_id,(select s_score from score where s_id=a.s_id and
c_id=‘01’) as 語文,
(select s_score from score where s_id=a.s_id and c_id=‘02’) as 數(shù)學(xué),
(select s_score from score where s_id=a.s_id and c_id=‘03’) as 英語,
round(avg(s_score),2) as 平均分 from score a GROUP BY a.s_id ORDER BY 平均分 DESC;
– 18.查詢各科成績最高分、最低分和平均分:以如下形式顯示:課程ID,課程name,最高分,最低分,平均分,及格率,中等率,優(yōu)良率,優(yōu)秀率
–及格為>=60,中等為:70-80,優(yōu)良為:80-90,優(yōu)秀為:>=90
select
a.c_id,b.c_name,MAX(s_score),MIN(s_score),ROUND(AVG(s_score),2),
ROUND(100*(SUM(case when a.s_score>=60 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 及格率,
ROUND(100*(SUM(case when a.s_score>=70 and a.s_score<=80 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 中等率,
ROUND(100*(SUM(case when a.s_score>=80 and a.s_score<=90 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 優(yōu)良率,
ROUND(100*(SUM(case when a.s_score>=90 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 優(yōu)秀率
from score a left join course b on a.c_id = b.c_id GROUP BY a.c_id,b.c_name
– 19、按各科成績進(jìn)行排序,并顯示排名(實(shí)現(xiàn)不完全)
– mysql沒有rank函數(shù)
select a.s_id,a.c_id,
@i:=@i +1 as i保留排名,
@k:=(case when @score=a.s_score then @k else @i end) as rank不保留排名,
@score:=a.s_score as score
from (
select s_id,c_id,s_score from score WHERE c_id=‘01’ GROUP BY s_id,c_id,s_score ORDER BY s_score DESC )a,(select
@k:=0,@i:=0,@score:=0)s
union
select a.s_id,a.c_id,
@i:=@i +1 as i,
@k:=(case when @score=a.s_score then @k else @i end) as rank,
@score:=a.s_score as score
from (
select s_id,c_id,s_score from score WHERE c_id=‘02’ GROUP BY s_id,c_id,s_score ORDER BY s_score DESC )a,(select
@k:=0,@i:=0,@score:=0)s
union
select a.s_id,a.c_id,
@i:=@i +1 as i,
@k:=(case when @score=a.s_score then @k else @i end) as rank,
@score:=a.s_score as score
from (
select s_id,c_id,s_score from score WHERE c_id=‘03’ GROUP BY s_id,c_id,s_score ORDER BY s_score DESC )a,(select
@k:=0,@i:=0,@score:=0)s
– 20、查詢學(xué)生的總成績并進(jìn)行排名
select a.s_id,
@i:=@i+1 as i,
@k:=(case when @score=a.sum_score then @k else @i end) as rank,
@score:=a.sum_score as score from (select s_id,SUM(s_score) as sum_score from score GROUP BY s_id ORDER BY sum_score DESC)a,
(select @k:=0,@i:=0,@score:=0)s
2.3 SQL 21-30
– 21、查詢不同老師所教不同課程平均分從高到低顯示
select a.t_id,c.t_name,a.c_id,ROUND(avg(s_score),2) as avg_score from course a
left join score b on a.c_id=b.c_id
left join teacher c on a.t_id=c.t_id
GROUP BY a.c_id,a.t_id,c.t_name ORDER BY avg_score DESC;
1
2
3
4
– 22、查詢所有課程的成績第2名到第3名的學(xué)生信息及該課程成績
select d.,c.排名,c.s_score,c.c_id from (
select a.s_id,a.s_score,a.c_id,@i:=@i+1 as 排名 from score a,(select @i:=0)s where a.c_id=‘01’
)c
left join student d on c.s_id=d.s_id
where 排名 BETWEEN 2 AND 3
UNION
select d.,c.排名,c.s_score,c.c_id from (
select a.s_id,a.s_score,a.c_id,@j:=@j+1 as 排名 from score a,(select @j:=0)s where a.c_id=‘02’
)c
left join student d on c.s_id=d.s_id
where 排名 BETWEEN 2 AND 3
UNION
select d.*,c.排名,c.s_score,c.c_id from (
select a.s_id,a.s_score,a.c_id,@k:=@k+1 as 排名 from score a,(select @k:=0)s where a.c_id=‘03’
)c
left join student d on c.s_id=d.s_id
where 排名 BETWEEN 2 AND 3;
– 23、統(tǒng)計(jì)各科成績各分?jǐn)?shù)段人數(shù):課程編號,課程名稱,[100-85],[85-70],[70-60],[0-60]及所占百分比
select distinct
f.c_name,a.c_id,b.85-100,b.百分比,c.70-85,c.百分比,d.60-70,d.百分比,e.0-60,e.百分比
from score a
left join (select c_id,SUM(case when s_score >85 and s_score <=100 then 1 else 0 end) as 85-100,
ROUND(100*(SUM(case when s_score >85 and s_score <=100 then 1 else 0 end)/count()),2) as 百分比
from score GROUP BY c_id)b on a.c_id=b.c_id
left join (select c_id,SUM(case when s_score >70 and s_score <=85 then 1 else 0 end) as 70-85,
ROUND(100(SUM(case when s_score >70 and s_score <=85 then 1 else 0 end)/count()),2) as 百分比
from score GROUP BY c_id)c on a.c_id=c.c_id
left join (select c_id,SUM(case when s_score >60 and s_score <=70 then 1 else 0 end) as 60-70,
ROUND(100(SUM(case when s_score >60 and s_score <=70 then 1 else 0 end)/count()),2) as 百分比
from score GROUP BY c_id)d on a.c_id=d.c_id
left join (select c_id,SUM(case when s_score >=0 and s_score <=60 then 1 else 0 end) as 0-60,
ROUND(100(SUM(case when s_score >=0 and s_score <=60 then 1 else 0 end)/count(*)),2) as 百分比
from score GROUP BY c_id)e on a.c_id=e.c_id
left join course f on a.c_id = f.c_id
– 24、查詢學(xué)生平均成績及其名次
select a.s_id,
@i:=@i+1 as ‘不保留空缺排名’,
@k:=(case when @avg_score=a.avg_s then @k else @i end) as ‘保留空缺排名’,
@avg_score:=avg_s as ‘平均分’
from (select s_id,ROUND(AVG(s_score),2) as avg_s from score GROUP BY s_id)a,(select @avg_score:=0,@i:=0,@k:=0)b;
– 25、查詢各科成績前三名的記錄
– 1.選出b表比a表成績大的所有組
– 2.選出比當(dāng)前id成績大的 小于三個(gè)的
select a.s_id,a.c_id,a.s_score from score a left join score b on a.c_id = b.c_id and a.s_score<b.s_scoregroup by a.s_id,a.c_id,a.s_score HAVING COUNT(b.s_id)<3ORDER BY a.c_id,a.s_score DESC
1
2
3
4
– 26、查詢每門課程被選修的學(xué)生數(shù)
select c_id,count(s_id) from score a GROUP BY c_id
1
– 27、查詢出只有兩門課程的全部學(xué)生的學(xué)號和姓名
select s_id,s_name from student where s_id in(
select s_id from score GROUP BY s_id HAVING COUNT(c_id)=2);
1
2
– 28、查詢男生、女生人數(shù)
select s_sex,COUNT(s_sex) as 人數(shù) from student GROUP BY s_sex
1
– 29、查詢名字中含有"風(fēng)"字的學(xué)生信息
select * from student where s_name like '%風(fēng)%';
1
– 30、查詢同名同性學(xué)生名單,并統(tǒng)計(jì)同名人數(shù)
select a.s_name,a.s_sex,count(*) from student a JOIN student b on a.s_id !=b.s_id and a.s_name = b.s_name and a.s_sex = b.s_sex
GROUP BY a.s_name,a.s_sex
1
2
3
2.4 SQL 31-40
– 31、查詢1990年出生的學(xué)生名單
select s_name from student where s_birth like ‘1990%’
1
– 32、查詢每門課程的平均成績,結(jié)果按平均成績降序排列,平均成績相同時(shí),按課程編號升序排列
select c_id,ROUND(AVG(s_score),2) as avg_score from score GROUP BY c_id ORDER BY avg_score DESC,c_id ASC
1
– 33、查詢平均成績大于等于85的所有學(xué)生的學(xué)號、姓名和平均成績
select a.s_id,b.s_name,ROUND(avg(a.s_score),2) as avg_score from score a
left join student b on a.s_id=b.s_id GROUP BY s_id HAVING avg_score>=85
1
2
– 34、查詢課程名稱為"數(shù)學(xué)",且分?jǐn)?shù)低于60的學(xué)生姓名和分?jǐn)?shù)
select a.s_name,b.s_score from score b LEFT JOIN student a on a.s_id=b.s_id where b.c_id=(select c_id from course where c_name ='數(shù)學(xué)') and b.s_score<60
1
2
– 35、查詢所有學(xué)生的課程及分?jǐn)?shù)情況;
select a.s_id,a.s_name,
SUM(case c.c_name when ‘語文’ then b.s_score else 0 end) as ‘語文’,
SUM(case c.c_name when ‘?dāng)?shù)學(xué)’ then b.s_score else 0 end) as ‘?dāng)?shù)學(xué)’,
SUM(case c.c_name when ‘英語’ then b.s_score else 0 end) as ‘英語’,
SUM(b.s_score) as ‘總分’
from student a left join score b on a.s_id = b.s_id
left join course c on b.c_id = c.c_id
GROUP BY a.s_id,a.s_name
– 36、查詢?nèi)魏我婚T課程成績在70分以上的姓名、課程名稱和分?jǐn)?shù);
select a.s_name,b.c_name,c.s_score from course b left join score c
on b.c_id = c.c_id
left join student a on a.s_id=c.s_id where c.s_score>=70
– 37、查詢不及格的課程
select a.s_id,a.c_id,b.c_name,a.s_score from score a left join course
b on a.c_id = b.c_id
where a.s_score<60
–38、查詢課程編號為01且課程成績在80分以上的學(xué)生的學(xué)號和姓名;
select a.s_id,b.s_name from score a LEFT JOIN student b on a.s_id = b.s_id
where a.c_id = ‘01’ and a.s_score>80
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– 39、求每門課程的學(xué)生人數(shù)
select count(*) from score GROUP BY c_id;
– 40、查詢選修"張三"老師所授課程的學(xué)生中,成績最高的學(xué)生信息及其成績
– 查詢老師id
select c_id from course c,teacher d where c.t_id=d.t_id and d.t_name=‘張三’
– 查詢最高分(可能有相同分?jǐn)?shù))
select MAX(s_score) from score where c_id=‘02’
– 查詢信息
select a.*,b.s_score,b.c_id,c.c_name from student a
LEFT JOIN Score b on a.s_id = b.s_id
LEFT JOIN course c on b.c_id=c.c_id
where b.c_id =(select c_id from course c,Teacher d where c.t_id=d.t_id and d.t_name=‘張三’)
and b.s_score in (select MAX(s_score) from Score where c_id=(select c_id from course c,Teacher d where c.t_id=d.t_id and
d.t_name=‘張三’))
2.5 SQL 41-50
– 41、查詢不同課程成績相同的學(xué)生的學(xué)生編號、課程編號、學(xué)生成績
select DISTINCT b.s_id,b.c_id,b.s_score from score a,score b where a.c_id != b.c_id and a.s_score = b.s_score
1
– 42、查詢每門功成績最好的前兩名
– 牛逼的寫法
select a.s_id,a.c_id,a.s_score from Score a
where (select COUNT(1) from Score b where b.c_id=a.c_id and b.s_score>=a.s_score)<=2 ORDER BY a.c_id
– 43、統(tǒng)計(jì)每門課程的學(xué)生選修人數(shù)(超過5人的課程才統(tǒng)計(jì))。要求輸出課程號和選修人數(shù),查詢結(jié)果按人數(shù)降序排列,若人數(shù)相同,按課程號升序排列
select c_id,count(*) as total from score GROUP BY c_id HAVING total>5
ORDER BY total,c_id ASC
– 44、檢索至少選修兩門課程的學(xué)生學(xué)號
select s_id,count(*) as sel from score GROUP BY s_id HAVING sel>=2
– 45、查詢選修了全部課程的學(xué)生信息
select * from student where s_id in( select s_id from score GROUP BY s_id HAVING count(*)=(select count(*) from course))
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–46、查詢各學(xué)生的年齡
– 按照出生日期來算,當(dāng)前月日 < 出生年月的月日則,年齡減一
select s_birth,(DATE_FORMAT(NOW(),’%Y’)-DATE_FORMAT(s_birth,’%Y’) -
(case when DATE_FORMAT(NOW(),’%m%d’)>DATE_FORMAT(s_birth,’%m%d’) then 0 else 1
end)) as age
from student;
– 47、查詢本周過生日的學(xué)生
select * from student where WEEK(DATE_FORMAT(NOW(),‘%Y%m%d’))=WEEK(s_birth)
select * from student where YEARWEEK(s_birth)=YEARWEEK(DATE_FORMAT(NOW(),‘%Y%m%d’))
select WEEK(DATE_FORMAT(NOW(),‘%Y%m%d’))
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– 48、查詢下周過生日的學(xué)生
select * from student where WEEK(DATE_FORMAT(NOW(),‘%Y%m%d’))+1 =WEEK(s_birth)
1
– 49、查詢本月過生日的學(xué)生
select * from student where MONTH(DATE_FORMAT(NOW(),’%Y%m%d’))
=MONTH(s_birth)
– 50、查詢下月過生日的學(xué)生
select * from student where MONTH(DATE_FORMAT(NOW(),‘%Y%m%d’))+1 =MONTH(s_birth)